A group of scientists produces a sample of potassium by extracting it from a giant truckload of bananas. 97.00 kg of the potassium is K-39 (38.897 amu), 21.00 kg of the potassium is K-40 (39.955 amu), and 11.00 kg of the potassium is K-41 (40.965 amu). What is the average atomic mass of the potassium in this sample?

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.

wanswer:

explanation: