For an atmospheric pressure of 97.3 kPa (abs) determine the heights of the fluid columns in barometers containing one of the following liquids: (a) mercury, (b) water, and (c) ethyl alcohol. Calculate the heights, including the effect of vapor pressure, and compare the results with those obtained neglecting vapor pressure ((d), (e), (f)). (g) Do these results support the widespread use of mercury for barometers

Follows are the solution to this question:

Explanation:

In the given question firstly we need to calculate the height of the pressure formula with in the vapor  pressure, that  includes the pressure, and its formula is:

The vapour pressure where pays any attention. Next mercury measurement,Ethyl alcohol and water.  

for mercury calculation:

a)

In the next step we calculate water value:

b)

In the last step, now we calculate the value of ethyl alchohol:

c)

The following would be the precise measurement of the heights without  

Pressure of the vapour:

It may draw the substantial inference from of the calculated values. For the very first time.  Mercury indicators and vapour pressure effects are insignificant and necessary  height is within acceptable values for the mercury barometer tube (imagine). The alcohol barometer tube 12 metres high!).

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"