What volume of acetic acid of density 1.10g/cm3 is needed to react with 250 mL of 0.50M Stronuim hydroxide?

Explanation:

Hello,

In this case, given the reaction in which the acetic acid reacts with strontium hydroxide to yield water and strontium acetate:

The first step here is to compute the moles of strontium hydroxide that are reacting given its volume in liters (0.250 L) and concentration:

Next, considering the 1:2 mole ratio between the strontium hydroxide and the acetic acid (molar mass = 60 g/mol) we compute the grams of acid that are consumed:

Then, by using the density of the acetic acid, we compute the volume:

Best regards.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

there is none because earth is stationary and flat.