When 50.0 mL of 1.00 M HCl(aq) and 50.0 mL of 1.00 M NaOH(aq) , both at 22.0 °C, are added to a coffee cup calorimeter, the temperature of the mixture reaches a maximum of 28.9 °C. What is the approximate amount of heat produced by this reaction? The specific heat of solution (4.18 J/g oC) and density of solution (1.00 g/mL)

The heat produced by this reaction is 2887J

Explanation:

The reaction of HCl with NaOH occurs as follows:

HCl + NaOH → H2O + NaCl + ΔH

Where ΔH is released heat due the reaction

The equation of a coffee cup calorimeter is:

Q = C*m*ΔT

Where Q is heat produced,

C is specific heat of the solution (4.18J/g°C),

m is mass of the solution (50mL + 50mL = 100mL = 100g -Because density is 1g/mL)

and ΔT is change in temperature (28.9°C - 22.0°C = 6.9°C)

Replacing:

Q = 4.184J/g°C*100g*6.9°C

Q = 2887J

The heat produced by this reaction is 2887J

the answer is 75.0%.