Draw the structure corresponding to the followingname:. a. (4Z,3S)-2,4,7-trimethyl-3-amino-4-o ctene
b. (3S,6R)-6-(2,4-dinitrophenyl)-3-ami no-1-heptyne

See figures 1 and 2

Explanation:

For this question, we can analyze each compound:

a. (4Z,3S)-2,4,7-trimethyl-3-amino-4-octene

In this case, we have to start with a carbon chain of 8 carbons. Then in carbons 2, 4 and, 7, we have to put three methyl groups (). In carbon 4 we have to put an amino group (). When we put the amino group in carbon 4 we will have a chiral carbon. So, we have to indicate the orientation in the bond of the amino group. If we want an "S" configuration the atoms must have a counterclockwise orientation. So, the amino group must have a dashed bond. Finally, in carbon 4 we have to put a double bond, the configuration of this double bond is "Z". So, the most important groups must be on the same side, in this case.

See figure 1 for further explanations

b. (3S,6R)-6-(2,4-dinitrophenyl)-3-amino-1-heptyne

In this case, we have to start with a chain of 7 carbons. In carbon 3 we have to put an amino group (). When we put this group in carbons we will have a chiral carbon is the name we have an "S" configuration for this carbon. So, we have to use the dashed bond in order to have a counterclockwise orientation for all the atoms bonded on carbon 3. In carbon 6 we have to put a big group "2,4-dinitrophenyl". In this group, we have a bond with the main carbon chain in carbon 6 (of benzene), in this same benzene ring we have to put nitro groups () in carbons 2 and 4. Additionally, carbon 6 is a chiral carbon, and the configuration of this carbon is "R". Therefore we have to use a wedge bond for all the "2,4-dinitrophenyl" in order to have a clockwise orientation for all the atoms bonded on carbon 6. Finally, we have to put a triple bond between carbons 2 and 3.

See figure 2 to further explanations

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.