Bombardier beetles inject boiling hydrogen peroxide, or H2O2, into the victims. It then decomposes into hydrogen and oxygen gas. How many grams of oxygen can be produced if 0.128 grams of hydrogen peroxide are decomposed?

0.12 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

H2O2 —> H2 + O2

Next, we shall determine the mass of H2O2 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:

Molar mass of H2O2 = (2×1) + (16×2)

= 2 + 32

= 34 g/mol

Mass of H2O2 from the balanced equation = 1 × 34 = 34 g.

Molar mass of O2 = 16×2 = 32 g/mol

Mass of O2 from the balanced equation = 1 × 32 = 32 g

Summary:

From the balanced equation above,

34 g of H2O2 decomposed to produce 32 g of O2.

Finally, we shall determine the mass of O2 produced from the decomposition of 0.128 g of H2O2. This can be obtained as follow:

From the balanced equation above,

34 g of H2O2 decomposed to produce 32 g of O2.

Therefore, 0.128 g of H2O2 will decompose to produce = (0.128×32)/34 = 0.12 g of O2.

Therefore, 0.12 g of O2 was produced.

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