A patient needs 40.0 mg of an antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms, how much antibiotic, in milligrams, should the patient receive each day for optimal therapy?

2,200 milligrams

Explanation:

40 mg per 1 kilogram means 40 times 55 which is 2,200 mg

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%