Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produces 3.52 g oxygen and 3.53 g sulfur, while the sulfur trioxide produces 9.00 g oxygen and 6.00 g sulfur. Calculate the mass of oxygen per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportions

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Explanation:

For sulphur dioxide;

3.53 g of sulphur combines with 3.52 g of oxygen

1.00 g of sulphur combines with 1.00 × 3.52/ 3.53 = 0.997 g

For sulphur trioxide

6.00 of sulphur combines with 9.00 g of oxygen

1.00 g of sulphur combines with 1.00 × 9.00/6.00 =1.5 g

Ratio of mass of oxygen;

1 : 1.5

The law of multiple proportions states that, if two elements A and B combine to form more than one chemical compounds, then the various masses of element A which combines separately with a fixed mass of element B are in simple multiple ratio.

We can see that the mass of oxygen which combines separately with sulphur in sulphur dioxide and sulphur trioxide are in simple ratio of 1:1.5.

answer

fusion: the energy source of stars. the energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. when the core is hot enough, nuclear fusion commences. fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

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