In titrating 0.20 M hydrochloric acid, HCl, with 0.20 M NaOH at 25°C, the solution at the equivalence point is

c) 0.10M NaCl

Explanation:

Options are:

a) 0.20M NaCl

b) Very acidic

c) 0.10M NaCl

d) 0.10M HCl + 0.20M NaOH

e) Slightly acidic.

Based on the reaction:

NaOH + HCl → H₂O + NaCl

You can see than 1 mole of NaOH reacts per mole of HCl producing 1 mole of NaCl

Assuming 1L of 0.20M HCl reacts with 1L of NaOH, moles of both compounds are:

1L * 0.20mol/L = 0.20 moles reacts. That means moles of NaCl produced are 0.20moles in 2L. Molarity of NaCl is:

0.20mol / 2L = 0.10M NaCl

That means, right option is:

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer