Draw a Lewis structure for BCl3 and answer the following questions based on your drawing. 1. For the central boron atom:
A. The number of lone pairs = ___
B. The number of single bonds = ___
C. The number of double bonds = ___
2. The central boron atom __
A. Obeys the octet rule
B. Has an incomplete octet.
C. Has an expanded octet.

1. For the central boron atom:

A. The number of lone pairs = 0.

B. The number of single bonds = 3.

C. The number of double bonds = 0.

2. The central boron atom B. Has an incomplete octet.

Explanation:

Hello,

In this case, as shown on the attached picture containing the required Lewis structure of boron chloride, we can see that:

1. For the central boron atom:

A. The number of lone pairs = 0 since all the three valance electrons are bonded with the chlorine atoms.

B. The number of single bonds = 3 as each chlorine atom needs only one bond to obey the octet.

C. The number of double bonds = 0 considering the previous explanation.

2. The central boron atom B. Has an incomplete octet since it reaches six electrons only from its initial three and other three provided by the three chlorine atoms.

Regards.

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

i think its 100

i hope this !