Amylose is chain of units connected by bonds. Cellulose is chain of units connected by bonds. a. e | D-fructose |
b. L-glucose |
c. B-1,6-glycosidic |
c. a-1,4-glycosidic |
d. a-1.6-glycosidic |
e. B-1,4-glycosidic |
f. a branched |
g. an unbrached |
h. L-fructose

The options are incomplete .

The correct one is D-glucose .

A. Amlyose is Unbranched, D-glucose,

connected by -1,4-glycosidic bond.

2. Cellulose is Unbranched chain D-glucose, connected by B-1,4-glycosidic bond

Explanation:

AMYLOSE is a polysaccharide that is made up of D glucose units which is connected by alpa 1, 4 glycosidic bond. It has a tight helical structure. It is a resistant starch that is not easily digested . It is an important animal digestive storage.

Cellulose is a polysaccharide also made up of D glucose and connected by beta 1,4 glycosidic bonds. cellulose . It is the major composition of plant cell walls. It give rigidity and strength to the cell wall.

The options to the question is incomplete, it should contain

D-glucose

1. Amylose- Unbranched, D-glucose, a-1,4-glycosidic

2. Cellulose- Unbranched, D-glucose, B-1,4-glycosidic

Explanation:

Amylose is one of the two polymeric components of starch, the other being amylopectin. Amylose is a polymer, made up of glucose monomers. In the structure of amylose, it is a linear (unbranched) chain of D-glucose subunits connected by α-1,4-glycosidic bonds.

On the other hand, cellulose is another polymer of glucose that makes up the cell wall of plant cells, conferring rigidity on it. It is a complex carbohydrate made up of many glucose units. Cellulose is an unbranched (linear) chain of D-glucose units connected by B-1,4-glycosidic bonds.

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.