For each name, draw the structure. a) (E)-5-Methyl-2-hexene
b) (S)-1,1,2-Trichloro-2-fluoroethane
c) 2,5-Diethyl-1-methylcyclohexanol

See figure 1

Explanation:

For this question, we can analyze each molecule:

-) (E)-5-Methyl-2-hexene

In this case, we have a carbon chain of 6 carbons. We have a double bond between carbons 3 and 2. Also, we have a methyl group is placed on carbon 5. Finally, the "E" configuration makes reference to the double bond,  the groups on each side of the double bond must have an opposite configuration.

-) 2,5-Diethyl-1-methylcyclohexanol

In this molecule, we have a carbon chain of 2 carbons. In carbon 2 we have two chlorine atoms. In carbon 1 we have a fluorine atom and a chlorine atom. The "S" configuration makes reference to carbon 1 (the chiral carbon), so we have to assign the priorities for each group bonded to carbon 1:

1 = Chlorine

2 = Fluorine

3 = Carbon 2

4 = Hydrogen

If we need an "S" configuration the priorities must be placed in such a way that we have a counterclockwise orientation.

-) 2,5-Diethyl-1-methylcyclohexanol

In this molecule, we have a cyclic carbon chain of 6 carbons. In carbon 1 we have an "OH" group and a methyl group. In carbon s 2 and 5, we have ethyl groups.

See figure 1

I hope it helps!

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