Calculations Weight of acetanilide = 2.7g
Theoretical yield of Nitroaniline =
Weight of para-nitroaniline = 1.5g
Percentage yield of para-nitroaniline =

Please help me which this and show me how you get the answer thank you

Theoretical yield: 2.75g of paranitroaniline

Percentage yield: 54.5%

Explanation:

In strong-acid medium, acetanilide (Molar mass: 135.16g/mol) reacts producing para-nitroaniline (138.12g/mol) in a 1/1 reaction.

Theoretical yield of para-nitroaniline is the mass produced assuming a yield of 100%. That is:

2.7g acetanilide × (1mol / 135.16g) = 0.020 moles of acetanilide.

Assuming a yield of 100% are 0.020 moles of paranitroaniline. Theoretical yield is:

0.020 moles × (138.12g / mol) =

Percentage yield is:

(Actual yield / theoretical yield) × 100

Actual yield was 1.5g and percentage yield will be:

Percentage yield: (1.5g / 2.75g) × 100

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

c. 75.7

i think that is the right