The volume of a gas is 8.0 L at 9.9°C and {P3} atm. What volume will the gas occupy if the temperature is raised to 9.3°C at constant pressure?
Select one:
O a. 7.98
Ob.0.263
C. 8.02
O d. 228

Option A. 7.98 L.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 8 L

Initial temperature (T1) = 9.9 °C

Final temperature (T2) = 9.3 °C

Final volume (V2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be achieved as shown below:

Temperature (K) = temperature (°C) + 273

T(K) = T (°C) + 273

Initial temperature (T1) = 9.9 °C

Initial temperature (T1) = 9.9 °C + 273 = 282.9 K

Final temperature (T2) = 9.3 °C

Final temperature (T2) = 9.3 °C + 273 = 282.3 K

Finally, we shall determine the new volume of the gas as follow:

Initial volume (V1) = 8 L

Initial temperature (T1) = 282.9 K

Final temperature (T2) = 282.3 K

Final volume (V2) =..?

V1/T1 = V2/T2

8/282.9 = V2/282.3

Cross multiply

282.9 x V2 = 8 x 282.3

Divide both side by 282.9

V2 = (8 x 282.3)/282.9

V2 = 7.98 L

Therefore, the new volume of the gas is 7.98 L

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prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.

i think its 100

i hope this !