Next, break down the equation shown into the skeletal half-reactions for oxidation and reduction. Which of these pairs shows the two skeletal half-reactions with their correct assignments?
reduction half reaction: HNO, NO
oxidation half reaction SH, SO,
oxidation half reaction: HNO3 -> NO
reduction half reaction: SH2SO,
reduction half reaction: HNO3 -H, SO,
oxidation half reaction S -> H2SO4

A:

reduction half reaction: HNO3-> NO

oxidation half reaction S->H2SO4

Explanation:

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o