Answer to the best of your ability please

The answer to your question is given below.

Explanation:

To draw the structure of 2–methyl–1–butanamine, we following must be observed:

1. The functional group of the compound is amine –NH2.

2. The functional group is located at carbon 1.

3. The longest continuous carbon chain is carbon 4 i.e butane. Since the functional group is amine, the –e at the end of the butane is replaced with

–amine, making the name to be butanamine.

4. Methyl, CH3 is located at carbon 2.

5. Combine the above to get the structure of 2–methyl–1–butaamine.

Please see attached photo for the structure of 2–methyl–1–butanamine

answer: i would say b.

explanation:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.