A mixture consisting of 0.120 mol N2, 0.018 mol O2, 0.112 mol CH4, and an unknown amount of CO2 occupies a volume of 9.04 L at 25°C and 1.17 atm pressure. Assuming that the gases all behave as ideal gases, how many moles of CO2 are there in this sample?

i don,t know so just answer mine

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

0.88m hope i am correct : )