Chemistry, 24.07.2020 21:01 sunshine52577oyeor9

Medical implants and high-quality jewelry items for body piercings are frequently made of a material known as G23Ti or surgical-grade titanium. The percent composition of the material is 64.39% titanium, 24.19% aluminum, and 11.42% vanadium. What is the empirical formula for surgical-grade titanium

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Answer from: izzynikkie

Using the stepwise procedure for obtaining the empirical formula of a compound, the empirical formula is $T_{6}Al_{4}V$

Titanium :

Percentage composition = 64.39%Molar mass = 47.87

Divide by Molar mass : = 64.39/47.87 = 1.345

Aluminum :

Percentage composition = 24.19%Molar mass = 27

Divide by Molar mass : = 24.19/27 = 0.896

Vanadium :

Percentage composition = 11.42%Molar mass = 50.94%

Divide by Molar mass : = 11.42/50.94 = 0.224

Divide by the smallest :

Titanium = 1.345 / 0.224 = 6.00

Aluminum = 0.896 / 0.224 = 4

Vanadium = 0.224 / 0.224 = 1

Hence, the empirical formula is $T_{6}Al_{4}V$

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Answer from: khynia11

The Empirical Formular is given as; Ti₆Al₄V

Explanation:

The percent composition of the material is 64.39% titanium, 24.19% aluminum, and 11.42% vanadium.

Elements Titanium Aluminium Vanadium

Percentage 64.39 24.19 11.42

Divide all through by their molar mass

64.39 / 47.87 24.19 / 27 11.42 / 50.94

= 1.345 = 0.896 = 0.224

Divide all though by the smallest number (0.224)

1.345 / 0.224 0.896 / 0.224 0.224 / 0.224

= 6 = 4 = 1

The Empirical Formular is given as; Ti₆Al₄V

Answer from: Quest

A) the enthralling of formation for pure element in its standard state is always positivehope this : )

Answer from: Quest

a electronegativity decreases beacuse the size of nucleus is bigger.

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