At 100 oC, Kc=0.36. If a 1.00-L flask initially contains 0.100 M N2O4, what will be the equilibrium concentration of NO2? N2O4(g)⇌2NO2(g)

Explanation:

Hello,

In this case, for the undergoing chemical reaction at equilibrium, the law of mass action for the equilibrium statement turns out:

Next, by introducing the reaction extent (ICE methodology) we can write:

Whereas the equilibrium constant is 0.36 and the initial concentration of dinitrogen tetroxide is 0.100 M:

Therefore, solving such quadratic equation we obtain two values of :

Clearly, the solution is 0.06M since the reaction extent must not be negative, thereby, the equilibrium concentration nitrogen dioxide turns out:

Best regards.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2