Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). (3 points) b 1. Adding hydrogen gas 2. Adding a catalyst 3. Decreasing the pressure a. Shift to the left b. Shift to the right c. No effect

1. b

2. c

3. a

Explanation: A chemical reaction in equilibrium is actually in a dynamic euqilibrium, which means that changing a condition will make the equilibrium move to counteract the action and reestate the equilibrium.

For example, in the reaction:

N2(g) + 3H2(g) ⇄ 2NH3(g)

1. Adding H2: if you add the reagent, to reestate the equilibrium, the reaction will produce more products so, it will move to the right;

2. A catalyst doesn't interfere in the equilibrium, because it moves to the right and to the left at the same extent. Therefore, there is no effect.

3. Decrease the pressure: when you decrease the pressure of a reaction, the equilibrium will make the pressure increase again by moving towards the side of the reaction which has more molecules, so, it shifts to the left;

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

beta decay is the answer