How many grams of NO are produced from 15.8 g of H2O

26.33 g of NO.

Explanation:

We'll begin by writing the balanced equation to produce NO from H2O. This is given below:

5N2 + 6H2O —> 4NH3 + 6NO

Next, we shall determine the mass of H2O that reacted and the mass of NO produced from the balanced equation. This is illustrated below:

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 6 x 18 = 108 g

Molar mass of NO = 14 + 16 = 30 g/mol

Mass of NO from the balanced equation = 6 x 30 = 180 g

From the balanced equation above,

108 g of H2O reacted to produce 180 g of NO.

Finally, we shall determine the mass of NO produced by the reaction of 15.8 g of H2O.

This is illustrated below:

From the balanced equation above,

108 g of H2O reacted to produce 180 g of NO.

Therefore, 15.8 g of H2O will react to produce = (15.8 x 180)/108 = 26.33 g of NO.

Therefore, 26.33 g of NO were obtained from the reaction.

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