Need help ASAP what is the value (angle) for the C=C=O bond in Ketene i. e. CH2=C=O

by the VSEPR theory.

Explanation:

This question is asking for the bond angle of the bond in . The VSEPR (valence shell electron pair repulsion) theory could help. Start by considering: how many electron domains are there on the carbon atom between these two bond?

Note that "electron domains" refer to covalent bonds and lone pairs collectively.

For example, in , the carbon atom at the center of that bond has two electron domains:

In VSEPR theory, electron domains around an atom repel each other. As a result, they would spread out (in three dimensions) as far away from each other as possible. When there are only two electron domains around an atom, the two electron domains would form a straight line- with one domain on each side of the central atom. (To visualize, consider the three atoms in this bond as three spheres on a stick. The central atom would be between the other atom and the atom.)

This linear geometry corresponds to a bond angle of .

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter