what products are formed if the compound is allowed to sit in d2O that contains a small amount of D2SO4

the products of the equations is D₃O⁺ + DSO₄⁻

Explanation:

attached is the diagram which explain the reaction

reaction of the equation

D₂O +  D₂SO₄ ----------- D₃O⁺ + DSO₄⁻

Note: in phenol, OH is in an ortho and para direction

ortho and para direction indicates direction of non-hydrogen substitute on hydrocarbon ring(benzene family)

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2