What is the value of the equilibrium constant Kcif the concentration of NO and NOBr are 0.10 M and the concentration of Br2 is 3.0 M?
2NOBr(8) = 2NO(g) + Br2(g)

3

Explanation:

Data obtained from the question include:

Concentration of NO, [NO] = 0.1M

Concentration of NOBr, [NOBr] = 0.1M

Concentration of Br, [Br2] = 3M

Equilibrium constant, Kc =..?

The equilibrium constant, Kc is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, the equilibrium constant, Kc for reaction can be obtained as follow:

2NOBr <==> 2NO + Br2

Kc = [NO]² [Br2] /[NOBr]²

[NO] = 0.1M

[NOBr] = 0.1M

[Br2] = 3M

Kc =..?

Kc = [0.1]² [3] /0.1]²

Kc = 3

Therefore, the equilibrium constant Kc, for the reaction is 3.

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

it's all four options.