Using the thermodynamic information , calculate the standard reaction entropy of the following chemical reaction: Round your answer to zero decimal places. 2Al(s)+ Fe2O3(s) → Al2O3(s)+ 2Fe(s)

The answer is "−847 J/K".

Explanation:

The given expression is:

2Al(s)+ Fe2O3(s) → Al2O3(s)+ 2Fe(s)

Δ ∑(Δ)

by the above definition Δ For Such a Component under standard conditions from its standard state, that also applies here. But, we start taking the overview and follow the conventions of signing:

Δ -847

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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