What is the [H30+) in a solution with (OH'] = 2.0 x 10-3 m? 2.0 x 10-3M
5.0 x 10-11M
2.0 x 10-12M
5.0 x 10-12 M
1.0 10-12 M

5.0 x 10-12 M

Explanation:

It is well known that; pH + pOH = 14.

pOH = - log [ OH-]

        =  - log [ 2.0 x 10 ∧-3]

        =  3 - log 2

        =   3  - 0.301 = 2.7 approximately.

recall that, pH + pOH = 14, therefore; pH = 14 - 2.7 = 11.3

pH = - log [ H3O+]

11.3 =  - log [H3O+], take the antilog of 11.3, gives us;

[H3O+] = antilog of - 11.3, which gives 5.0 x 10-12 M

i would say b

explanation:

but i think i would need more information than that