What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O (l) ⇄ NH₄⁺ (aq) + OH⁻ (aq)

11.4

Explanation:

Step 1: Given data

Step 2: Write the dissociation equation

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

Step 4: Calculate the pOH

We will use the following expression.

Step 5: Calculate the pH

We will use the following expression.

ok whats the question if not i cannot you i need question and need a thing to answer