If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limiting reagent? 2Al + 3CuCl -> 2AlCl3 + 3Cu

Copper (II) chloride.

Explanation:

Hello,

In this case, considering the described reaction which is also given as:

For us to identify the limiting reactant we first compute the available moles of aluminium:

Next, we compute the consumed moles of aluminium by the 1147 grams of copper (II) chloride by using their 2:3 molar ratio:

Thereby, we can infer aluminium is in excess since less moles are consumed than available whereas the copper (II) chloride is the limiting reactant.

Best regards.

your picture is not part of the scientific method.

it's all four options.