10 Points Determine the enthalpy change
of the following reaction: CH4 +
4Cl2 -> CCl4 + 4HCI
Given enthalpies:
CH4: -17.9 kJ/mol
Cl2: 0 kJ/mol
CCl4: -95.98 kJ/mol
HCI: -92.3 kJ/mol
A. -170.38
B.-206.18
C.-447.28 kJ/mol
OD.-393.58
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it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.