1) In 1.31 g of a chloride of titanium, there is 0.528 g of titanium. What is the empirical formula of this titanium chloride?

TiCl2

Explanation:

Mass of the chloride of titanium= 1.31 g

Mass of titanium= 0.528 g

Therefore mass of chlorine = 1.31-0.528 = 0.782 g

To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.

Ti- 0.528/48 = 0.011, Cl- 0.782/35.5 = 0.022

Ti- 0.011/0.011 , Cl- 0.022/0.011

Ti- 1, Cl-2

Hence the required empirical formula is TiCl2

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.