You have 3.00 m3 of a fixed mass of a gas at 150 kPa. Calculate the pressure if the volume is reduced to 1.20 m3 at a constant temperature.

Solution:

Explanation:

V1   =   3.00m3

T1   =    150kPa

V2  =   1.20m3

T2  =     x

As ,

    V1    =    V2

     T1            T2

    3.00  =  1.20

      150        X

3.00 x X  =  150 x  1.20

3.00X  =   180

X   =  180

         3.00

X  =  60 kPa

what does the table look like

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).