Using the following equation how many moles of KClO3 are required if 6.9 moles of O2 are formed?

Number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles.

Explanation:

The decomposition of potassium trioxochlorate(v) by heat to produce potassium chloride and oxygen gas is given by the balanced chemical equation below;

2KClO3(s) > 2KCl(s) + 3O2(g)

From the equation of the reaction, 2 moles of KClO3 produces 3 moles of oxygen gas when it decomposes under standard conditions of temperature and pressure.

The mole ratio of KClO3 to oxygen gas

is 2:3

When 6.9 moles of oxygen gas is produced, (2/3) * 6.9 moles of KClO3 will be required = 4.6 moles of KClO3

Therefore, number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles

i think that the answer is c

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )