A. When comparing the two elements Ca and As , the more metallic element is: based on periodic trends alone. b. When comparing the two elements Ca and As , the more metallic element is: based on periodic trends alone.
c. When comparing the two elements Sb and Pb , the more metallic element is: based on periodic trends alone.
d. When comparing the two elements S b and P b , the more metallic element is: based on periodic trends alone.

Ca.

Sb.

Explanation:

a. When comparing the two elements Ca and As , the more metallic element is: based on periodic trends alone.

The correct option is Ca. Ca belongs to group 2 which is more easily give off it's electrons, compared to As which is a group 5 member.

c. When comparing the two elements Sb and Pb , the more metallic element is: based on periodic trends alone.

The correct option here is Pb. Thhs is because ionization energy decreases down the group. Pb has a lower ionization enthalpy than Sb

a) Ca

b) Ca

c) Pb

d) Pb

Explanation:

We must have it behind our minds that metallic properties decreases as we tend towards the right and side of the periodic table. This implies that we find more metallic species at the left hand did of the periodic table and as we tend towards the right hand side, elements become less metallic as indicated by periodic trends.

Calcium is a group 2 metal with full metallic properties while arsenic is a metalloid. Similarly, lead is a group 14 metal with full metal properties while antimony is a metalloid. Hence the answers given above.

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

0.88m hope i am correct : )