The microscopic neutron absorption cross section for Boron at 0.0253 ev is 759 b. Calculate the microscopic neutron absorption cross section for Boron at 200 ev. Assume 1/v behavior

first one is the correct answer

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

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