How much heat is required to change 25.0 g of water from solid to liquid at 0 oC? Water: ΔHfus = 334 J/g; ΔHvap= 2260J/g

The heat required to change 25.0 g of water from solid ice to liquid water at 0°C  is 8350 J

Explanation:

The parameters given are

The temperature of the solid water = 0°C

The heat of fusion,   = 334 J/g

The heat of vaporization, = 2260 J/g

Mass of the solid water = 25.0 g

We note that the heat required to change a solid to a liquid is the heat of fusion, from which we have the formula for heat fusion is given as follows;

ΔH =  m ×

Therefore, we have;

ΔH =  25 g × 334 J/g = 8350 J

Which gives the heat required to change 25.0 g of water from solid ice to liquid water at 0°C  as 8350 J.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890