Chemistry, 01.07.2020 22:01 savannnab1890

Hydrochloric acid and sodium hydroxide can be combined to form sodium chloride and water. Which best explains the reaction? The mass of sodium hydroxide will result in the same mass of sodium chloride. The total mass of hydrochloric acid and sodium hydroxide will result in a lower total mass of sodium chloride and water. The mass of hydrochloride acid will result in the same mass of sodium chloride. The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water.

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The correct answer to the question is: The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water.

Chemical equation is backed up by the law of conservation of matter (mass) which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to the other.

Thus,

The total mass of reactants is equal to the total mass of products.

For example: let us consider the reaction between hydrogen and oxygen to produce water

2H₂ + O₂ —> 2H₂OReactant:

2H₂ = 2(2×1) = 2(2) = 4 g

O₂ = 2 × 16 = 32 g

Total mass = 4 + 32 = 36 gProduct:

2H₂O = 2[(2×1) + 16]

= 2[2 + 16]

= 2[18]

Total mass = 36 g

Thus,

Mass of reactant = mass of product

From the above illustration, we can conclude that the total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water.

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Answer from: queenfan1818

The statement "The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water." is true due to the Law of Conservation of Mass which states that matter cannot be created nor destroyed.

Answer from: Quest

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

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Hydrochloric acid and sodium hydroxide can be combined to form sodium chloride and water. Which best...

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