g Draw all possible monochlorinated products of 2,3-dimethylbutane reacting with Cl2 and light. Choose one and draw a mechanisms for its formation (use the worksheet as a guide; same mechanism as bromination but with chlorine).

See the explanation

Explanation:

In this case, we have to remember that we have a reaction that goes by radical formation. On the other hand, we have to write only the monochlorinated products this means that we only can add one Cl atom at the time. So, in this specific molecule, we only can have 2 options, 1-chloro-2,3-dimethylbutane and 2-chloro-2,3-dimethylbutane. (See figure 1).

In the reaction mechanism, we have as a first step the production of the radical chlorine Cl. This radical can attack the molecule by a heterolytic rupture and form a carbon-radical. As the final step, the carbon-radical will attack another Cl radical to form a new C-Cl bond. (See figure 2)

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