What percent of a drug is contained in a mixture of powder consisting of 0.5 kg, containing 0.038% of a drug, and 10 kg, containing 0.043% of a drug?

Explanation:

In this question, we have to start with the calculation of the amount of drug in each powder:

Powder A: Total mass of 0.5 Kg percentage of 0.038%

Powder B: Total mass of 10 Kg percentage of 0.043%

The total mass of powder would be:

The total mass of drug would be:

Now we can calculate the percentage:

I hope it helps!

dynamic equilibrium is the answer.