Consider the expected splitting of the C2 proton signal in the 1H NMR spectrum of 2-ethyl-1,3-propanediol. Presuming that the coupling constants for neighboring protons are sufficiently different, and that the instrument has sufficient resolving power, what is the theoretical multiplicity of the C2 proton signal? a. 12
b. 15
c. 0
d. 6

Seven

Explanation:

In this case, in the middle carbon; (carbon 2) we have 3 neighbors. In the left and right carbon, we have 4 hydrogens in total. In the top carbon, we have 2 hydrogens also, so, in total, we have 6 hydrogens. If we follow the n+1 rule, we will have:

n= 6

signals= n + 1 = 6 + 1 = 7

So, we will have a signal of 7 (a septet).

See figure 1

I hope it helps!

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

Ithink its solid. hope this