In the SN2 portion of this experiment, an alcohol is converted into an alkyl halide. In the SN1 portion, alkyl halides are converted into alcohols. How are these apparently opposite reactions possible?Consider leaving groups and thermodynamics, rather than mechanism. SN2- 1-butanol to 1-bromobutane
SN1- 2-bromo-2-methylbutane to 2-methyl-2-propanol

i think is conclusions.i think so

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally