How many grams of chlorine gas are needed to react with 3.5 liters of a 1.7 molar potassium bromide solution?
Cl2 + 2 KBr - 2 KCl + Br2

211.2 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 1.7 M

Volume of solution = 3.5 L

Putting values in equation 1, we get:

The balanced chemical reaction is:

According to stoichiometry:

2 mole of KBr requires = 1 mole of

5.95 moles of KBr requires = moles of

Mass of

Thus 211.2 grams of chlorine gas are needed to react with 3.5 liters of a 1.7 molar potassium bromide solution

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

the answers would be

the first one and the second one