A sample of wood with a mass of 30 g has its temperature changed from 10° to 45° C. In the
process, it releases 90 J of heat. What is its specific
heat?

0.086J/g°C

Explanation:

The following data were obtained from the question:

Mass (M) = 30g

Initial temperature (T1) = 10°C

Final temperature (T2) = 45°C

Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C

Heat (Q) released = 90J

Specific heat capacity (C) of wood =..?

We can obtain the specific heat capacity of the wood as follow:

Q = MCΔT

90 = 30 x C x 35

Divide both side by 30 x 35

C = 90/(30 x 35)

C = 0.086J/g°C.

Therefore, the specific heat capacity of the wood is 0.086J/g°C.