Select the best answer for the question. 13. A reversible reaction has an equilibrium constant of 0.75. If the forward rate constant is 0.62 mol/L/s, what's the
reverse reaction rate constant?
A. 1.210
B. 0.827
O C. 0.910
D. 1.010

B

Explanation:

The rate constant is equal to forward rate divided by reverse rate.

K = f/r

-> r = f/K

0.62/0.75 = 0.8267

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

that's what i got you can count the number of atoms