There is a double tube exchanger, in which you have glycerin flowing in the inner tube at a rate of 2.5 Kg / s, it enters at a temperature of 600 ° C and it exits at a temperature of 100 ° C, and from the outside you have water which enters at a temperature of 20 ° C, at a rate of 1.0 Kg / s, if the resistance to total heat flow is 150 KW/m^2*K, determine the value of the conduction coefficient of the pipe, if the inner pipe it is nominal 1 1/2 "Schedule 80, and the outer piping is nominal 2" Schedule 80. The system is in parallel with flows large enough to neglect convection.

3 hours because it is a decent distance.

lol idk man i guess u gotta ask bill nye the science guy

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole