Draw the major organic product formed by reaction of 2-hexyne with the following reagent: H2O in H2SO4/HgSO4
Consider E/Z stereochemistry of alkenes.
In cases where there is more than one answer, just draw one.
If no reaction occurs, draw the starting material.

We will have 2 products

a) hexan-3-one

b) hexan-2-one

Explanation:

We have to remember that this reaction will produce a ketone (with a previous enol formation). Additionally, this reaction is a markovnikov reaction, so the C=O group would be added in the most substituted carbon, but in this case, in the triple bond, we have the same substitution, both carbons in the triple bond are secondary carbons. So, we will have two products, the C=O group be added in the left carbon of the triple bond and the right carbon of the triple bond.

See figure 1

I hope it helps!

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

i'm assuming that it's c.) red bank..