What is the molarity of a solution containing 9.478 grams of rucl3 in enough water to make 1.00 l of solution?

Molar mass RuCl3 = 207.4290 g/mol

number of moles 

9.478 / 207.4290 => 0.0456 moles

M = n / V

M = 0.0456 / 1.00 (L)

= 0.0456 M

668900 atoms in total

Ch4 and ph3 are both covalent since they are composed both of non-metals.    ch4 is non- polar because of  london forces and has a geometry of tetrahedral  ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf