A chemist must dilute of aqueous iron(II) bromide solution until the concentration falls to . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits.

22.9 mL

Explanation:

use dilution formula

M1×V1 = M2×V2

1---> is for stock solution

2---> is for diluted solution

Assuming the values not given in the question

M1 = 2.41 M

M2 = 2.0 M

V1 = 19.0 mL

Use:

M1×V1 = M2×V2

V2 = (M1×V1) / M2

V2 = (2.41×19)/2

V2 = 22.9 mL

22.9 mL

explanation:

detials on each model with digrams

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.