A compound X of molecular formula C8H12 with no triple bonds reacts with one equivalent of H2 to give a new compound having molecular formula C8H14. What can be inferred about the structure of compound X? Group of answer choices Compound X has 2 rings and 1 p bond. Compound X has 1 ring and 2 p bonds. Compound X has 3 rings. Compound X has 3 p bonds.

Compound X has 3 p bonds.

Explanation:

Since the question asks for the structure of the compound, we are going to use the index of hydrogen deficiency (IHD) formular to obtain this.

Since our unknown compound contains on;y carbon and hydrogen, the IHD formula us reduced to;

Degree of unsaturation = ( 2C + 2  - H) / 2

Imputing the number of carbon and hydrogen atoms, we have;

Degree of unsaturation = (2 * 8 + 2 - 12) / 2 = 3

This value tells us the sum of multiple bonds and rings present.

The fact that i reacts with H2n to guve C8H14 means it contains at least one double bond.

Time to go over the options give;

Compound X has 2 rings and 1 p bond.

This option is wrong because the resulting structure shall be a bicyclo compound and won't react with the H2.

Compound X has 1 ring and 2 p bonds

This is also wrong

Compound X has 3 rings

This is wrong.

Compound X has 3 p bonds.

This is correct. This means that C8H12 is an octatriene that reacted with H2 to give octadiene; C8H14

it is the most commonly accepted one

the answer is c. nacl