Consider that you have a balloon containing 2.00 moles of CO and 1.00 mole of O2 which is in a room that has a temperature of 25.8oC and a pressure of 1.00 atm. Then, the following reaction occurs inside the balloon to completion: 2 CO(g) + O2(g) -> 2 CO2(g). Calculate the change in work due to the reaction occurring inside the balloon.

Work is equivalent to pressure multiplied by length. Work occurs when there is movement in the direction of the force. The SI unit of work is the joule (J), and the further calculation can be defined as follows:

Given:

Pressure= 1.00 atm

Temperature

Given equation:

Converting the temperature to :

Calculating the value:

Calculating work:

Therefore, the final answer is "-2.48 KJ".

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Explanation:

1. Calculate the moles of CO₂ formed

              2CO  +  O₂  ⟶ 2CO₂

n/mol:     2.00    2.00

The molar ratio is 2 mol CO₂:2 mol CO.

2. Calculate the change in the number of moles

We started with 3.00 mol of gas and ended with 2.00 mol.

Δn = n₂ - n₁ = 2.00 mol - 3.00 mol = -1.00 mol

3. Calculate the work done

(a) Convert the temperature to kelvins

T = (25.8 + 273.15) K = 298.95 K

(b) Calculate the work

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.