If the [Na+] = 0.250 M in a Na3P solution, calculate the concentration of Phosphorous ions and the number of grams of Na3P required to make 1.50 L of the solution

[P³⁻] = 0.083 M

Mass of Na₃P required: 12.5 g

Explanation:

We dissociate the salt, like this:

Na₃P → 3Na⁺  +  P³⁻

It is a ionic salt that can be dissociated.

As [Na⁺] is 0.25M, ratio is 3:1.

For 3 moles of sodium cathion, I have 1 mol of salt

So, for 0.25 moles of Na⁺, we have (0.25 . 1)/3 = 0.083M

So ratio with the anion is 1:1. In conclussion, [P³⁻] = 0.083 M

Finally, we have to know that molarity is mol/L so:

M = mol/L → 0.083mol/L = moles /1.50L

To make 1.50 L of solution, we need 0.083 mol/L . 1.50L = 0.125 moles

Let's find out the mass, with the molecular weight:

0.125 mol . 99.97g / 1mol = 12.5 g

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

answer; natural resources;